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Friday, 23 October 2015
UVA 10783 (Odd Sum)
Solution ::
#include <stdio.h>
int main ()
{
int i,t,a,b,m,n;
scanf("%d",&t);
for(i=1;i<=t;i++){
int sum=0;
scanf("%d %d",&a,&b);
if(a%2!=0){
n=a;
}
if(a%2==0){
n=a+1;
}
for(m=n;m<=b;m=m+2){
sum=sum+m;
}
printf("Case %d: %d\n",i,sum);
}
return 0;
}
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